I have a problem that seems really basic, but for whatever reason I keep messing up...

f(r) = 7/(1+r)^2

Find the average value of the function on the interval [1,5]

I let u = 1+r

so   du = dx

and integral 7u^-2 du

integrated I get -7u^(-1)  and the new interval is [2,6]

-7(6)^-1+7(2)^-1 = 7/3

So the answer I keep coming up with is 7/3 which is wrong evidently........ Can anyone help?

Views: 32

Replies to This Discussion

ah, I didn't know I had to multiply it by 1/(b-a) for the average value of a function.  So  7/3 * 1/(5-1) = 7/12.....

This problem was probably so basic that you guys didn't bother with it, lol.  Ugh, I get stuck on the dumbest things.  At least now I'll remember that. 

RSS

Support Atheist Nexus

Donate Today

Donate

 

Help Nexus When You Buy From Amazon

Amazon

Nexus on Social Media:

Latest Activity

Donald L. Engel liked John Jubinsky's discussion New Tattoos Found on Oetzi the Iceman
5 minutes ago
Michael Penn replied to Zoie Rayne's discussion So many issues with coming out....
13 minutes ago
Loren Miller replied to Loren Miller's discussion Beer, Beer, Glorious Beer! in the group Food!
23 minutes ago
sk8eycat commented on Daniel W's group Food!
24 minutes ago
MagetheEntertainer posted a video

Religion Ruining Sex

All about religion, and its negative impact on human sexuality
32 minutes ago
sk8eycat commented on Daniel W's group Food!
41 minutes ago
Dr. Terence Meaden liked John Jubinsky's discussion New Tattoos Found on Oetzi the Iceman
43 minutes ago
Michael Penn replied to Loren Miller's discussion Beer, Beer, Glorious Beer! in the group Food!
45 minutes ago

© 2015   Atheist Nexus. All rights reserved. Admin: Richard Haynes.

Badges  |  Report an Issue  |  Terms of Service